I saw that teams must play 6 games to be eligible for the B1G championship, which I didn't realize before. So if Wiscy misses two more games, they would be ineligible?
That is correct but note that this provision is only active IF B1G teams averaged six or more games. If the average number of games played by all B1G teams is less than six then the eligibility threshold is "no fewer than two less games than the average". Further, as I understand it, the average is rounded to the nearest whole game so in order for this provision to be activated the average for all other teams would have to drop below 5.5.
Example: Suppose that the following occur:
- Wisconsin misses three games and plays five, going 5-0.
- One other B1G team missed three games.
- All other B1G teams miss two games each.
The average for all B1G teams would be 5.86 (82 games played by 14 teams, 82/14=5.86). That IS less than six, but as I understand it, they round the average so it is six not "less than six" so Wisconsin is ineligible.
At this point we have one cancellation so, if all other games are played, the average will be 7.86.
The goofy thing to keep an eye on for now is that if Wisconsin ends up 6-1 while a B1G-W team that plays all eight games loses to Wisconsin and finishes 7-1, Wisconsin will go to the B1GCG, NOT the 7-1 B1G-W team that has a better winning percentage. This is because if two teams are tied in the loss column and have a different number of wins the H2H winner prevails.
Note, however, that this applies only to teams tied in the loss column, not teams tied in the win column. Thus, if Wisconsin goes 6-1 while another B1G-W team beats Wisconsin and goes 6-2, Wisconsin goes to the B1GCG based on their superior winning percentage.
Maybe I'm reading something wrong, but it seems like that favors teams that miss a game.
