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First, UMD, RU, and IU are all mathematically eliminated because they each have at least four losses and tOSU can do no worse than 6-3. 

Second, Penn State IS mathematically still in the B1GCG race but BARELY.  The best they could do is a 4-way tie at 6-3 with the Buckeyes, Spartans, and Wolverines but they WOULD win that tie.  Here is everything that would need to happen to get there, then the tiebreaker that PSU would win:

What would need to happen:

• PSU would need to win out (vsM, vsRU, @MSU)
• tOSU would need to lose out (vsPU, vsMSU, @M)
• MSU would need to lose their other game (vsUMD)
• M would need to lose their other game (@UMD)

In that case PSU, tOSU, MSU, and M would all finish 6-3 in conference and the first tiebreaker is H2H2H2H where it would be:

• 2-1 PSU (beat MSU/M, lost to tOSU)
• 2-1 MSU (beat M/tOSU, lost to PSU)
• 1-2 tOSU (beat PSU, lost to MSU/M)
• 1-2 M (beat tOSU, lost to PSU/MSU)

The rules state that if only two teams are left after any tiebreaker, those two teams revert to the two-team H2H tiebreaker.  Thus, once tOSU and M were eliminated on the 4-way H2H2H2H, the Spartans and Nittany Lions would revert to their H2H were PSU would win. 

Thus, PSU would win a 4-way B1G-E tie at 6-3. 

Penn State's mathematical chance is obviously an EXTREMELY minute chance realistically because they need a specific result in each of a multitude of games.  Even if each one was individually fairly likely, the chances of all of them are remote. 

That leaves the three serious contenders:

• 6-0 Ohio State:  Controls their own destiny. 
• 5-1 Michigan State:  Controls their own destiny but has MUCH less margin for error than they had last week. 
• 5-1 Michigan:  Needs help but is in a lot better shape than they were last week.  All they need is one MSU loss and they regain control of their own B1GCG (and probably CFP) destiny.