I somehow managed to completely forget the divionless B12 in my earlier post, here is the situation in that league:
- 6-0 Baylor: Would almost clinch a B12CG spot with a win over Oklahoma this weekend. With that win they would be 7-0 and could do no worse than 7-2. Only Oklahoma (5-2) and Texas (4-2) could catch them and they would own the H2H tiebreaker over Oklahoma. In theory they could still finish in a three-way tie*
- 5-1 Oklahoma: Would almost clinch a B12CG spot with a win over Baylor this weekend. With that win they would be 6-1 and own H2H victories over Baylor, Texas, and ISU. They would, however, lose a 6-3 tie with either KSU or OkSU or both.
- 4-2 Texas: The shortest path for the Longhorns is to win out (@ISU, @Baylor, vsTxTech) and for Oklahoma to beat Baylor. In that case the Longhorns would finish tied with Baylor and they would win that tie. See three-team tiebreaker below for the event of a three-way tie at 7-2 between TX, OU, and Baylor.
- 3-3 KSU: The Wildcats have that nice H2H win over Oklahoma but it isn't going to matter unless Oklahoma starts losing. The problem is that KSU has losses to Baylor, Texas, and OkSU so they need a lot of help.
- 3-3 OkSU: The Cowboys would need a lot of help. They can't do any better than a tie with Baylor and they lost to Baylor. They also lost to Texas but they haven't played OU yet. In theory they could get in, but it would require multiple losses by both Texas and Oklahoma.
- 3-3 Iowa State: The Cyclones have losses to Baylor, Oklahoma, and OkSU so they would need even more help than the Cowboys.
- 2-4 TCU: In theory the Frogs could make it but it would require an epic collapse by Oklahoma along with unlikely losses by Texas, OkSU, and ISU.
- 2-4 Texas Tech: I think that the Raiders are mathematically eliminated because they can't catch Baylor and could only possibly tie Oklahoma. They already lost to Oklahoma so they would lose a two-way tie but realistically if they ended up tied with OU at 5-4 there would almost have to be other teams involved in that tie.
- 1-5 WVU and Kansas: These two are definitely mathematically eliminated because they can do no better than 4-5.
*Three team scenario and tiebreaker:
The scenario:
- Texas wins out (@ISU, @Baylor, vsTxTech) and finishes 7-2/9-3
- Oklahoma loses exactly one of their three remaining games (@Baylor, vsTCU, @OkSU) and finishes 7-2/10-2
- Baylor loses exactly one other game (in addition to losing to Tx) and finishes 7-2/10-2
The B12's first tiebreaker is H2H2H. Texas would be 1-1 with a win over Baylor and a loss to Oklahoma.
If Oklahoma beats Baylor then:
- Oklahoma is in (2-0 H2H2H)
- Texas is in (1-1 H2H2H)
- Baylor is out (0-2 H2H2H)
If Baylor beats Oklahoma then:
The H2H2H would be all tied up at 1-1 each (OU>TX>Baylor>OU).
The next tiebreaker is record against the next best B12 team, then the next, then the next, etc. At this point it is too early to determine that. Each team's other loss would be to:
- OU's other loss would be to KSU, currently 3-3.
- Texas' other loss would be to TCU, currently 2-4.
- Baylor's other loss would be to Kansas, currently 1-5.
KSU has the best current record AND the easiest remaining schedule so the most likely outcome is that the three teams would be compared based on their records against KSU which would eliminate Oklahoma and send the Longhorns and Bears to the B12CG.
I really hate this tiebreaker and the B1G uses it as well. It is trying to reward good wins but the problem, IMHO, is that by doing that it inherently penalizes "good" losses. Ie, in this scenario, Baylor's "other" loss would be to a woeful Kansas team. That, to me, is a LOT worse than Oklahoma's and Texas' losses to TCU and KSU.